4(2x-1)(3-5x)=3/4-3x^2

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Solution for 4(2x-1)(3-5x)=3/4-3x^2 equation: 



4(2x-1)(3-5x)=3/4-3x^2

We move all terms to the left:

4(2x-1)(3-5x)-(3/4-3x^2)=0



Domain of the equation: 4-3x^2)!=0

We move all terms containing x to the left, all other terms to the right

-3x^2)!=-4

x!=-4/1

x!=-4

x∈R



We add all the numbers together, and all the variables

-(3/4-3x^2)+4(2x-1)(-5x+3)=0

We get rid of parentheses

3x^2+4(2x-1)(-5x+3)-3/4=0

We multiply parentheses ..

3x^2+4(-10x^2+6x+5x-3)-3/4=0

We multiply all the terms by the denominator


(4(-10x^2+6x+5x-3))*4+3x^2*4-3=0

Wy multiply elements

(4(-10x^2+6x+5x-3))*4+12x^2-3=0

We add all the numbers together, and all the variables

12x^2+(4(-10x^2+6x+5x-3))*4-3=0

We move all terms containing x to the left, all other terms to the right

12x^2+(4(-10x^2+6x+5x-3))*4=3

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